In the given reaction $C_6H_5-C(=O)-CH_3$ $\xrightarrow{NH_2OH/H^{+}} X$ $\xrightarrow{Na/C_2H_5OH} Y$. $Y$ will be:

  • A
    $C_6H_5-CH(NH_2)-CH_3$
  • B
    $C_6H_5-CH(CH_3)-NH-CH_3$
  • C
    $C_6H_5-CO-NH-CH_3$
  • D
    $CH_3-CO-NH-C_6H_5$

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